Get to know the math and engineering calculation of hydraulics.
Basic Formulas
Pressure, Force and Horsepower Relationships :
Pressure (psi) = force (lbs) / area (in²)
Force (lbs) = area (in²) x pressure (psi)
Area (in²) = force (lbs) / pressure (psi)
Fluid Power Horsepower (hp) = pressure (psi) x pump flow (gpm) / 1,714
Torque (ft lbs) = horsepower (hp) x 5,252 / speed (rpm)
Horsepower (hp) = torque (ft lbs) x speed (rpm) / 5,252
Speed (rpm) = horsepower (hp) x 5,252 / torque (ft lbs)
(Can also use 3.1416 x radius squared (ins) )
Piston Rod End (annulus end) Area (in²) = piston cylinder area (in²) – rod area (in²)
Cylinder Force (lbs) = pressure (psi) x area (in²)
Cylinder Speed (ft/min) = 19.25 x flow rate (gpm) / area (in²)
(Divide by 60 to convert speed to ft/sec)
Cylinder Speed (in/min) = flow rate (cu ins/min) / area (in²)
(Note that 1 US gallon = 231 cu ins)
Cylinder Time (secs) = area (in²) x cylinder stroke (ins) x .26 / flow rate (gpm)
Cylinder Flow Rate (gpm) = 12 x 60 x cylinder speed (ft/sec) x area (in²) / 231
Cylinder Volume Capacity (gals) = cylinder area (in²) x cylinder stroke (ins) / 231
Pump Outlet Flow (gpm) = pump speed (rpm) x pump displacement (cu ins/rev) / 231
Pump Speed (rpm) = 231 x pump flow rate (gpm) / pump displacement (cu ins/rev)
Pump Horsepower (hp) = flow rate (gpm) x pressure (psi) / 1,714 x pump efficiency factor
(Can also use horsepower (hp) = torque (in lbs) x pump speed (rpm) / 63,025)
Pump Torque (in lbs) = pressure (psi) x pump displacement (cu ins/rev) / 6.28
(Can also use horsepower (hp) x 63,025 / pump displacement (cu ins/rev)
One US gallon equals:
- 231 cubic inches
- 3.785 liters (1 liter = .2642 US gals)
- 4 quarts or 8 pints
- 128 ounces liquid / 133.37 ounces weight
- 8.3356 pounds weight
On psi equals:
- .0689 bar (1 bar = 14.504 psi)
- 6.895 kilopascal
- 2.0416 hg (inches of mercury)
- 27.71” water
One atmosphere equals:
- 14.696 psi
- 1.013 bar
- 29.921 hg (inches of mercury)




